Optimal. Leaf size=146 \[ -\frac{b^2 (1-2 p) (1-p) \left (a+b \sqrt [3]{x}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{a^3 \sqrt [3]{x}}+\frac{b (1-p) \left (a+b \sqrt [3]{x}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{a^2 x^{2/3}}-\frac{\left (a+b \sqrt [3]{x}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{a x} \]
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Rubi [C] time = 0.0985437, antiderivative size = 162, normalized size of antiderivative = 1.11, number of steps used = 7, number of rules used = 3, integrand size = 77, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.039, Rules used = {1356, 266, 65} \[ \frac{2 b^3 (1-2 p) (1-p) p \left (\frac{b \sqrt [3]{x}}{a}+1\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p \, _2F_1\left (1,2 p+1;2 (p+1);\frac{\sqrt [3]{x} b}{a}+1\right )}{a^3 (2 p+1)}+\frac{3 b^3 \left (\frac{b \sqrt [3]{x}}{a}+1\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p \, _2F_1\left (4,2 p+1;2 (p+1);\frac{\sqrt [3]{x} b}{a}+1\right )}{a^3 (2 p+1)} \]
Antiderivative was successfully verified.
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Rule 1356
Rule 266
Rule 65
Rubi steps
\begin{align*} \int \left (\frac{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{x^2}-\frac{2 b^3 (1-2 p) (1-p) p \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{3 a^3 x}\right ) \, dx &=-\frac{\left (2 b^3 (1-2 p) (1-p) p\right ) \int \frac{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{x} \, dx}{3 a^3}+\int \frac{\left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{x^2} \, dx\\ &=\left (\left (1+\frac{b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \int \frac{\left (1+\frac{b \sqrt [3]{x}}{a}\right )^{2 p}}{x^2} \, dx-\frac{\left (2 b^3 (1-2 p) (1-p) p \left (1+\frac{b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \int \frac{\left (1+\frac{b \sqrt [3]{x}}{a}\right )^{2 p}}{x} \, dx}{3 a^3}\\ &=\left (3 \left (1+\frac{b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \operatorname{Subst}\left (\int \frac{\left (1+\frac{b x}{a}\right )^{2 p}}{x^4} \, dx,x,\sqrt [3]{x}\right )-\frac{\left (2 b^3 (1-2 p) (1-p) p \left (1+\frac{b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \operatorname{Subst}\left (\int \frac{\left (1+\frac{b x}{a}\right )^{2 p}}{x} \, dx,x,\sqrt [3]{x}\right )}{a^3}\\ &=\frac{2 b^3 (1-2 p) (1-p) p \left (1+\frac{b \sqrt [3]{x}}{a}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p \, _2F_1\left (1,1+2 p;2 (1+p);1+\frac{b \sqrt [3]{x}}{a}\right )}{a^3 (1+2 p)}+\frac{3 b^3 \left (1+\frac{b \sqrt [3]{x}}{a}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p \, _2F_1\left (4,1+2 p;2 (1+p);1+\frac{b \sqrt [3]{x}}{a}\right )}{a^3 (1+2 p)}\\ \end{align*}
Mathematica [C] time = 0.0877713, size = 101, normalized size = 0.69 \[ \frac{b^3 \left (a+b \sqrt [3]{x}\right ) \left (\left (a+b \sqrt [3]{x}\right )^2\right )^p \left (2 p \left (2 p^2-3 p+1\right ) \, _2F_1\left (1,2 p+1;2 (p+1);\frac{\sqrt [3]{x} b}{a}+1\right )+3 \, _2F_1\left (4,2 p+1;2 (p+1);\frac{\sqrt [3]{x} b}{a}+1\right )\right )}{a^3 (2 a p+a)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.01, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{2}} \left ({a}^{2}+2\,ab\sqrt [3]{x}+{b}^{2}{x}^{{\frac{2}{3}}} \right ) ^{p}}-{\frac{2\,{b}^{3} \left ( 1-2\,p \right ) \left ( 1-p \right ) p}{3\,{a}^{3}x} \left ({a}^{2}+2\,ab\sqrt [3]{x}+{b}^{2}{x}^{{\frac{2}{3}}} \right ) ^{p}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{2 \,{\left (b^{2} x^{\frac{2}{3}} + 2 \, a b x^{\frac{1}{3}} + a^{2}\right )}^{p} b^{3}{\left (2 \, p - 1\right )}{\left (p - 1\right )} p}{3 \, a^{3} x} + \frac{{\left (b^{2} x^{\frac{2}{3}} + 2 \, a b x^{\frac{1}{3}} + a^{2}\right )}^{p}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.69189, size = 186, normalized size = 1.27 \begin{align*} -\frac{{\left (a^{2} b p x^{\frac{1}{3}} + a^{3} +{\left (2 \, b^{3} p^{2} - 3 \, b^{3} p + b^{3}\right )} x + 2 \,{\left (a b^{2} p^{2} - a b^{2} p\right )} x^{\frac{2}{3}}\right )}{\left (b^{2} x^{\frac{2}{3}} + 2 \, a b x^{\frac{1}{3}} + a^{2}\right )}^{p}}{a^{3} x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{2 \,{\left (b^{2} x^{\frac{2}{3}} + 2 \, a b x^{\frac{1}{3}} + a^{2}\right )}^{p} b^{3}{\left (2 \, p - 1\right )}{\left (p - 1\right )} p}{3 \, a^{3} x} + \frac{{\left (b^{2} x^{\frac{2}{3}} + 2 \, a b x^{\frac{1}{3}} + a^{2}\right )}^{p}}{x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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